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-2x^2+8x=8
We move all terms to the left:
-2x^2+8x-(8)=0
a = -2; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·(-2)·(-8)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-8}{-4}=+2$
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